CHAOS SUDOKU

Even though the rules of classic Sudoku apply in Chaos Sudoku, other laws prevail here. The chaotic arrangement of the boxes results in many interesting new solutions.

The challenge is to keep track and thus bring order to the chaos.

Terms

Boxes

The main difference between a Chaos Sudoku and a classic Sudoku are the boxes. In the figure, one box is highlighted at a time.One Sudoku all boxes have an individual random shape. Additionally, depending on the difficulty level, the boxes may have been moved one or more steps. This will cause them to be torn apart, or they may even be continued on the opposite side of the board. Another type of box is randomly distributed on the board when the Sudoku is created. Thus it is possible that this box has no adjacent cells at all.

Nevertheless, it is still true for all these boxes that each number in them may occur only once.

Boxes

Nevertheless, it is still true for all these boxes that each number in them may occur only once.

Chaos Sudoku with a box spreaded over the play area

Row, Column, and Cell

In the example of a 7x7 Sudoku, the row 3 (horizontal), the column F (vertical) and the cell F3 are highlighted. This information refers to a coordinate system in which the columns get letters between A and F (or between A and I for 9x9 Sudokus) and the rows get numbers between 1 and 7 (respectively 1 and 9). Thus, a single cell can be found by specifying coordinates.

Row, Column, and Cell

Variants

One Sudoku offers Chaos Sudokus in the sizes 7x7 to 12x12 and in 4 different difficulty levels. These differ as with classical Sudokus by the number of givens and the associated necessary number of solution steps. In addition, the chaos level increases with each level of difficulty.

Sizes beginning from 10x10 can be played on devices with a larger screens.

Rules

The same basic rule apply to Chaos Sudokus as to Classic Sudokus: In each column, each row and each box, each number may occur only exactly once.

Solving Steps

Step 1

In this 7x7 Chaos Sudoku there are 7 rows, 7 columns and 7 boxes. The boxes are unevenly distributed across the board. The highlighted box even has no adjacent cells at all.

Step 1

In this 7x7 Chaos Sudoku there are 7 rows, 7 columns and 7 boxes. The boxes are unevenly distributed across the board. The highlighted box even has no adjacent cells at all.

Step 2

As a starting step, we can first uncover all the 1s. If we click on one of the given 1, we can see that cell G5 is the only possibility for the 1 in this box. For all other cells in this box, it is blocked by other 1s.

Step 2

Step 3

The last remaining hidden 1 is at E2. For this box no number 1 has been uncovered yet and also in this column and row there is no 1 - so this cell is the last possibility.

Step 3

The last remaining hidden 1 is at E2. For this box no number 1 has been uncovered yet and also in this column and row there is no 1 - so this cell is the last possibility.

Step 4

For the number 2 we see in cell B5 the last possibility for this box. All other cells are blocked by given twos.

This 2 also allows us to uncover the 2 in E4 as the last possible position for this box.

Step 4

For the number 2 we see in cell B5 the last possibility for this box. All other cells are blocked by given twos.

This 2 also allows us to uncover the 2 in E4 as the last possible position for this box.

Step 5

We can uncover the two hidden 4s as a last possibilities in cells G4 and B1.

Step 5

We can uncover the two hidden 4s as a last possibilities in cells G4 and B1.

Step 6

For the number 3 only one given is available at C5. Nevertheless, we can already use it to uncover cell G6, since the given 3 blocks the other two cells of this box that have not yet been solved.

The 3 can then also be entered for cells A7 and B2; here, too, all other cells are blocked.

Step 6

For the number 3 only one given is available at C5. Nevertheless, we can already use it to uncover cell G6, since the given 3 blocks the other two cells of this box that have not yet been solved.

The 3 can then also be entered for cells A7 and B2; here, too, all other cells are blocked.

Step 7

The last 3 we can solve at this time is the 3 in cell D4, which belongs to the box spread across the board. The last 3s not solved are respectively in cells E and F of lines 1 and 3, which we can note down for now.

Step 7

Step 8

We have only one 5 on the whole field as a given. Nevertheless, we can note down two pairs for the 5 in column C and row 4. In these boxes, the 5 can only be in one of these two positions, because the other cells are blocked by our given 5.

With the help of these two pairs, the 5 is blocked for this column and row. This allows us to uncover the 5 for cell A5.

Step 8

With the help of these two pairs, the 5 is blocked for this column and row. This allows us to uncover the 5 for cell A5.

Step 9

The next 5 can be solved for cell B7. In this box, cell G3 is blocked by the pair from the previous step. We can also exclude the 5 for cell F2. Our pair column C and the box enclosing F2 force a 5 to occur in one of these boxes - and thus not in our box - in the first two rows.

Step 9

Step 10

With our newly discovered 5, we can note the 5 as a pair in the cells D6 and E6. Due to the same situation as in the previous step, together with the group in row 3, the 5 for cells D1 and E1 can be excluded.

For the box at the top right, this leaves cell G2 as the last possible position for the number 5. With this, we can also dissolve the group in column C and enter the 5 in cell C1.

Step 10

For the box at the top right, this leaves cell G2 as the last possible position for the number 5. With this, we can also dissolve the group in column C and enter the 5 in cell C1.

Step 11

In row 3 we can write down a group for number 2. This has created a group of three consisting of 2, 3 and 5, which blocks these 3 cells for other numbers. Therefore, for this box, we can note down a group of 6 and 7 in cells A4 and B4.

The same group of three also blocks the three cells for row 3. For this reason, we can also determine 6 and 7 as the last possibilities for the other two cells in this row. Since the 7 is already given in cell G1, it can be entered in cell A3 for line 3 and the 6 in the last free cell G3.

As a bonus, we have thus also already uncovered the first 6, for which we had no clues before.

Step 11

As a bonus, we have thus also already uncovered the first 6, for which we had no clues before.

Step 12

Because of our good progress in the last step, we can write down the 6 and the 7 in more cells as a solution. In addition, we can write down more groups in lines 5 and 6.

By adding the new group with the number 6 in line 1, we also see that for cell E1, 3 is the only possible solution. By revealing this 3 and thus solving the other groups where the 3 is omitted as a possibility, we can solve the Sudoku completely.

Step 12

Because of our good progress in the last step, we can write down the 6 and the 7 in more cells as a solution. In addition, we can write down more groups in lines 5 and 6.

Step 13

The finally solved Chaos Sudoku.

Step 13

The finally solved Chaos Sudoku.

CHAOS SUDOKU

Terms

Boxes

Boxes

Row, Column, and Cell

Row, Column, and Cell

Variants

Rules

Solving Steps

Step 1

Step 1

Step 2

Step 2

Step 3

Step 3

Step 4

Step 4

Step 5

Step 5

Step 6

Step 6

Step 7

Step 7

Step 8

Step 8

Step 9

Step 9

Step 10

Step 10

Step 11

Step 11

Step 12

Step 12

Step 13

Step 13

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